x^2+6x+9=(16+x-3)(x-3)

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Solution for x^2+6x+9=(16+x-3)(x-3) equation: 



x^2+6x+9=(16+x-3)(x-3)

We move all terms to the left:

x^2+6x+9-((16+x-3)(x-3))=0

We add all the numbers together, and all the variables

x^2+6x-((x+13)(x-3))+9=0

We multiply parentheses ..

x^2-((+x^2-3x+13x-39))+6x+9=0



We calculate terms in parentheses: -((+x^2-3x+13x-39)), so:

(+x^2-3x+13x-39)

We get rid of parentheses

x^2-3x+13x-39

We add all the numbers together, and all the variables

x^2+10x-39

Back to the equation:

-(x^2+10x-39)



We add all the numbers together, and all the variables

x^2+6x-(x^2+10x-39)+9=0

We get rid of parentheses

x^2-x^2+6x-10x+39+9=0

We add all the numbers together, and all the variables

-4x+48=0

We move all terms containing x to the left, all other terms to the right

-4x=-48

x=-48/-4

x=+12

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